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Rowing Split Calculator

Convert 500 m splits to watts, finish times and predicted 2k results

Updated · Free, no signup

m

Used for the finish time and as the base for Paul’s Law predictions.

Result

263 W

Average power

263 W

500 m split

1:50.0 /500m

Time for this distance

7:20.0

Time for this distance

7m 20s

Monitor calories per hour

1,205 kcal/h

Weight-adjusted calories per hour

1,205 kcal/h

Predicted 2k time (Paul’s Law)

7:20.0
  • Rowing 2 seconds faster (1:48.0) needs 278 W — 5.7% more power.
  • Distance covered in 30 minutes at this split: 8,182 m.

Predicted 500 m split by distance (seconds)

Paul’s Law predictions from this piece

DistancePredicted splitPredicted timeWatts
500 m1:40.01:40.0350
1,000 m1:45.03:30.0302
2,000 m1:50.07:20.0263
5,000 m1:56.619:26.1221
6,000 m1:57.923:35.1213
10,000 m2:01.640:32.2195
Half marathon2:07.01:29:18.4171

About the Rowing Split Calculator

On a rowing machine everything comes back to the 500 m split — the time it would take to row 500 metres at your current speed. This rowing split calculator converts a split into watts using the Concept2 formula, or works backwards from watts to split, then gives the finish time for any piece distance and the calories per hour shown on the performance monitor.

It is designed for indoor rowers, crews and CrossFit athletes who train on a Concept2 or similar erg: plan target splits for a 2k test, translate a watts-based workout into splits, compare pieces of different lengths, or check how much harder a 2-second faster split really is (power rises with the cube of speed, so small split gains cost a lot of watts).

The prediction table uses Paul’s Law, a rowing rule of thumb that your split slows by about 5 seconds per 500 m every time the distance doubles. It works best between 500 m and 10k and for rowers with balanced speed and endurance; treat it as a pacing guide, not a guarantee.

How to use the rowing split calculator

  1. 1Choose whether you are starting from a 500 m split or average watts.
  2. 2Enter the split (minutes and seconds) or the watts.
  3. 3Enter the distance of the piece you rowed or plan to row.
  4. 4Optionally add your body weight for adjusted calories.
  5. 5Read watts, finish time and the predicted splits for other distances.

Formula and method

Watts = 2.80 ÷ (split ÷ 500)³
Split = 500 × ∛(2.80 ÷ watts)
Time = split × distance ÷ 500
Paul’s Law: split₂ = split₁ + 5 × log₂(d₂ ÷ d₁)

Concept2 performance monitors convert pace to power with watts = 2.80 ÷ pace³, where pace is seconds per metre (the 500 m split divided by 500). Because power depends on the cube of speed, cutting your split by a few seconds takes a disproportionately large increase in watts. Finish time is simply the split multiplied by the number of 500 m segments.

Monitor calories per hour are estimated as 4 × 0.8604 × watts + 300 (mechanical power to kcal at about 25% efficiency plus a resting allowance for a 175 lb rower); Concept2’s weight correction subtracts 300 and adds 1.714 × body weight in pounds. Predictions use Paul’s Law, which adds 5 seconds to the split each time distance doubles.

split
Time per 500 m in seconds
d₁, d₂
Known piece distance and target distance (m)
watts
Average power on the monitor

Worked examples

1:50.0 split for a 2k

A 1:50 split is 0.22 s/m, so watts = 2.80 ÷ 0.22³ = 263.0 W. Four 500 m segments take 4 × 110 = 440 s, a 7:20.0 2k. The monitor shows about 263 × 3.4416 + 300 = 1,205 kcal/h.

200 watts for 5,000 m

Split = 500 × ∛(2.80 ÷ 200) = 120.5 s (2:00.5). Ten segments make 1,205 s, about 20:05 for 5k. Paul’s Law predicts a 2k split 5 × log₂(2,000 ÷ 5,000) = 6.6 s faster — 1:53.9, or about 7:35.6 for 2,000 m.

Predicting a 2k from a 500 m test

A 1:35.0 500 m is 0.19 s/m, or 2.80 ÷ 0.19³ = 408.2 W. Two doublings from 500 m to 2,000 m add 10 seconds, predicting a 1:45.0 split and a 7:00.0 2k. For an 80 kg (176.4 lb) rower the weight-adjusted burn is about 408.2 × 3.4416 + 1.714 × 176.4 ≈ 1,707 kcal/h.

Frequently asked questions

How do I convert a 500m split to watts?+

Divide the split in seconds by 500 to get seconds per metre, cube it, and divide 2.80 by the result. A 2:00 split is 0.24 s/m, giving 2.80 ÷ 0.013824 ≈ 203 W. A 1:45 split works out to about 302 W.

What is a good 2k erg time?+

It depends heavily on age, sex, body weight and training history, so there is no single benchmark. The fairest comparison is the Concept2 online logbook rankings, which you can filter by age group, sex and weight class to see where your time sits.

What is Paul’s Law in rowing?+

Paul’s Law is a widely used rowing rule of thumb: each time you double the distance, your 500 m split slows by about 5 seconds. A 1:40 500 m suggests roughly 1:45 for 1k and 1:50 for 2k.

Why does a small split change need so many more watts?+

Water and the erg’s fan resist motion roughly with the cube of speed, so power scales with the cube of pace. Going from a 2:00 to a 1:50 split — about 9% faster — requires about 30% more watts.

Are erg calories accurate?+

The monitor assumes a 175 lb rower and about 25% mechanical efficiency, so lighter people are over-credited and heavier people under-credited. Concept2’s adjustment (subtract 300, add 1.714 × your weight in lb) gives a fairer estimate.

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