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Charles's Law Calculator

Solve V₁/T₁ = V₂/T₂ with automatic Kelvin conversion

Updated · Free, no signup

Answer

2.5031

In the volume or temperature unit you selected.

Result

V₂ = 2.5031 L

T₁ in kelvin

298.15 K

T₂ in kelvin

373.15 K

Volume change factor V₂/V₁

1.2516

  • Each 1 K (1 °C) change alters the volume by 0.335% of V₁ — about 1/298.2.
  • Temperatures were converted to kelvin before dividing — using °C or °F directly gives wrong answers.

Volume vs temperature at constant pressure

About the Charles's Law Calculator

This Charles's law calculator finds how the volume of a gas changes with temperature when pressure is held constant, or what temperature is needed to reach a target volume. Pick the unknown — V₁, T₁, V₂ or T₂ — and enter the other three. You can type temperatures in Celsius, Kelvin or Fahrenheit; the calculator converts them to Kelvin behind the scenes, which is the step most people forget.

It is useful for chemistry students, for explaining why a balloon shrinks in the freezer or a tyre looks flat on a cold morning, and for rough checks on hot-air balloons and gas thermometers. The chart shows the straight-line relationship between volume and absolute temperature.

The law assumes an ideal gas, a closed container that can expand freely (constant pressure) and a fixed amount of gas. Temperatures at or below absolute zero (0 K, −273.15 °C) are not physically meaningful and are rejected.

With the default inputs, the answer is 2.5031. Change any value above to recalculate instantly.

How to use the charles's law calculator

  1. 1Choose which value to solve for.
  2. 2Select your temperature unit (°C, K or °F) and volume unit.
  3. 3Enter the three known values.
  4. 4Read the answer; kelvin equivalents are shown for checking your working.

Formula and method

V₁ / T₁ = V₂ / T₂ → V₂ = V₁ × T₂ / T₁, T₂ = T₁ × V₂ / V₁ (T in kelvin)

Charles's law states that at constant pressure, the volume of a fixed amount of ideal gas is directly proportional to its absolute temperature. Plotting volume against temperature gives a straight line that extrapolates to zero volume at absolute zero, −273.15 °C.

Because the proportionality only holds on an absolute scale, the calculator first converts every temperature to kelvin (K = °C + 273.15, or K = (°F − 32) × 5/9 + 273.15), solves the ratio, and converts a temperature answer back to your chosen unit. Volumes can be in any unit as long as both states match.

V₁, V₂
Initial and final volume
T₁, T₂
Initial and final absolute temperature (K)

Worked examples

Heating a gas from 25 °C to 100 °C

Convert to kelvin: 298.15 K and 373.15 K. Then V₂ = 2 × 373.15 ÷ 298.15 ≈ 2.503 L — a 25% rise, not the fourfold increase the Celsius numbers would suggest.

Balloon in the freezer

A 5 L balloon at 22 °C (295.15 K) cooled to −18 °C (255.15 K) shrinks to 5 × 255.15 ÷ 295.15 ≈ 4.32 L.

Temperature needed to expand a gas

To grow 400 mL at 300 K to 500 mL, T₂ = 300 × 500 ÷ 400 = 375 K (about 101.85 °C).

Frequently asked questions

What is Charles's law?+

Charles's law says that at constant pressure the volume of a gas is directly proportional to its absolute temperature: V₁/T₁ = V₂/T₂. Heating a gas makes it expand; cooling makes it contract.

Why must temperature be in kelvin for Charles's law?+

The law is a direct proportion, which only works on a scale that starts at true zero. On the Celsius scale 0 °C is not zero energy, so ratios of Celsius temperatures give wrong answers. Kelvin starts at absolute zero.

What is the difference between Charles’s law and Boyle’s law?+

Charles's law relates volume and temperature at constant pressure. Boyle's law relates pressure and volume at constant temperature. The combined gas law merges both.

What are everyday examples of Charles's law?+

Hot-air balloons rise because heated air expands and becomes less dense; a basketball feels softer outdoors in winter; a sealed bag of chips puffs up in a hot car.

What happens at absolute zero?+

Extrapolating Charles’s law, an ideal gas would reach zero volume at 0 K (−273.15 °C). Real gases liquefy long before that, which is why the calculator rejects temperatures at or below absolute zero.

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