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RLC Impedance Calculator

Impedance, phase angle and reactance of series and parallel RLC circuits

Updated · Free, no signup

Ω

0 = no resistor.

mH

0 = no inductor.

µF

0 = no capacitor.

Hz
V

Impedance |Z|

138.846 Ω

Phase angle

-43.93 °

Positive = inductive (current lags), negative = capacitive (current leads).

Rectangular form

100 − j96.323 Ω

Inductive reactance XL

62.832 Ω

Capacitive reactance XC

159.155 Ω

Current from source

0.072 A

Power factor (cos φ)

0.7202

Resonant frequency

1,591.55 Hz

Circuit behaves as

Capacitive (current leads voltage)
  • L and C resonate at 1.592 kHz; there XL = XC and the series circuit drops to its minimum impedance, R.
  • Your frequency is below resonance, so the capacitor dominates the reactance.
  • 10 V RMS drives 72.02 mA through this impedance.

Impedance magnitude vs frequency

About the RLC Impedance Calculator

This RLC impedance calculator works out the total impedance of a resistor, inductor and capacitor connected either in series or in parallel, at the frequency you choose. It returns the impedance magnitude |Z| in ohms, the phase angle between voltage and current, the individual inductive and capacitive reactances, the rectangular form R + jX, the current drawn from a given AC voltage, and the resonant frequency of the L–C pair.

It is useful for electronics students checking homework, technicians sizing filters, crossovers and snubbers, and engineers estimating how a load behaves on an AC supply. Leave L or C at zero to analyse simpler RL, RC or LC circuits — a zero value means that component is simply not in the circuit.

The math assumes ideal components: pure resistance, an inductor with no winding resistance and a capacitor with no leakage or ESR. A sweep chart shows how |Z| changes over two decades around your frequency, so you can see the dip (series) or peak (parallel) at resonance.

With the default inputs, the impedance |z| is 138.846 Ω. Change any value above to recalculate instantly.

How to use the rlc impedance calculator

  1. 1Choose whether the components are in series or in parallel.
  2. 2Enter R in ohms, L in millihenries and C in microfarads (0 removes a part).
  3. 3Enter the operating frequency and, optionally, the source voltage.
  4. 4Read |Z|, the phase angle and the rectangular form R + jX.
  5. 5Check the sweep chart to see where resonance falls relative to your frequency.

Formula and method

XL = 2πfL · XC = 1 ÷ (2πfC) · Series: Z = √(R² + (XL − XC)²), φ = atan((XL − XC) ÷ R) · Parallel: 1/Z = √((1/R)² + (ωC − 1/XL)²)

Inductors and capacitors oppose AC with reactance that depends on frequency: XL = 2πfL rises with frequency while XC = 1/(2πfC) falls. In a series circuit the reactances subtract and combine with the resistance at right angles, so |Z| = √(R² + X²) with X = XL − XC, and the phase angle is atan(X/R).

In a parallel circuit the calculator adds admittances instead: conductance G = 1/R and susceptance B = ωC − 1/XL, then Z = 1/(G + jB), giving |Z| = 1/√(G² + B²) and φ = −atan(B/G). Resonance occurs at f0 = 1/(2π√(LC)), where XL = XC. Components are ideal; a value of zero removes that component from the circuit.

R
Resistance (Ω)
L
Inductance (H; entered in mH)
C
Capacitance (F; entered in µF)
f, ω
Frequency in Hz and angular frequency 2πf
XL, XC
Inductive and capacitive reactance (Ω)
φ
Phase angle of the impedance
f0
Resonant frequency

Worked examples

Series 100 Ω, 10 mH, 1 µF at 1 kHz

XL = 2π × 1000 × 0.01 = 62.83 Ω and XC = 1/(2π × 1000 × 1e−6) = 159.15 Ω, so the net reactance is −96.32 Ω. |Z| = √(100² + 96.32²) ≈ 138.85 Ω at −43.9°, a capacitive circuit. 10 V drives about 72 mA.

Motor-style RL load with a 10 µF capacitor at 60 Hz

At 60 Hz, XL = 37.70 Ω and XC = 265.26 Ω, a net −227.56 Ω. With 50 Ω of resistance, |Z| = √(50² + 227.56²) ≈ 232.99 Ω and the phase is −77.6°, so the capacitor dominates far below the 159 Hz resonance.

Parallel 1 kΩ, 10 mH, 1 µF at 1 kHz

G = 1/1000 = 0.001 S and B = ωC − 1/XL = 0.006283 − 0.015915 = −0.009632 S. |Z| = 1/√(0.001² + 0.009632²) ≈ 103.26 Ω with a +84.1° phase: below resonance the inductor carries most of the current, so the parallel circuit looks inductive.

Frequently asked questions

What is impedance in an RLC circuit?+

Impedance is the total opposition to alternating current, combining resistance with the reactance of inductors and capacitors. It is a complex quantity with a magnitude in ohms and a phase angle, written Z = R + jX.

What happens at resonance?+

At f0 = 1/(2π√LC) the inductive and capacitive reactances are equal and cancel. A series RLC circuit then has its minimum impedance (just R) and maximum current; a parallel circuit has its maximum impedance.

What does a negative phase angle mean?+

A negative phase angle means the circuit is capacitive: current leads the voltage. A positive angle means it is inductive and current lags the voltage. Zero means it behaves like a pure resistor.

How do I calculate an RC or RL circuit with this tool?+

Set the unused component to zero. With L = 0 you get a series or parallel RC circuit; with C = 0 you get an RL circuit. Zero means the part is absent, not a short.

Why does impedance change with frequency?+

Inductive reactance grows in proportion to frequency (XL = 2πfL) while capacitive reactance shrinks (XC = 1/2πfC). Only the resistor is frequency-independent, so the overall impedance varies with frequency.

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